Vector Is Not A Template

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The code is parsed in the order it appears. Vector in the function signature. Template void some_func( std::vector<t,a> const& vec ) { } the second argument is the allocator, and in some advanced usage of std::vector it will not be. Anyway define a type instead of a macro. Building on what ganesh said, if you arrived here anytime after 2019,.

Vector Is Not A Template

The same result can however be achieved by simply including in the header file, this way you are not dependant on the order of inclusion. This however is rather unwielding. Therefore the compiler needs to know the declaration of std::vector at that point (amongst other things,.</p> The type of the vector you want to create is of the same kind.

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Just get iter underlying type either using decltype or using iterator. As some commenters have noted, you have circular references. This however is rather unwielding. Template void some_func( std::vector<t,a> const& vec ) { } the second argument is the allocator, and in some advanced usage of std::vector it will not be. Therefore the compiler needs to know the declaration of.

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The same result can however be achieved by simply including in the header file, this way you are not dependant on the order of inclusion. Vector is a template, not a type, you need the template argument list e.g. Commented jun 24, 2020 at 9:39. The type of the vector you want to create is of the same kind of.

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Therefore the compiler needs to know the declaration of std::vector at that point (amongst other things,.</p> You have to do this because vector is defined in the std. The type of the vector you want to create is of the same kind of iter. This however is rather unwielding. Anyway define a type instead of a macro.

Vector Is Not A Template - You're getting the errors because u64 is not defined at that point. The same result can however be achieved by simply including in the header file, this way you are not dependant on the order of inclusion. Commented jun 24, 2020 at 9:39. Building on what ganesh said, if you arrived here anytime after 2019, you need #include and the std::vector to use a vector. The code is parsed in the order it appears. If we start in node.h, early on, it includes edge.h.

This however is rather unwielding. Vector is a template, not a type, you need the template argument list e.g. Therefore the compiler needs to know the declaration of std::vector at that point (amongst other things,.</p> Everywhere qualify it by std:: Template void some_func( std::vector<t,a> const& vec ) { } the second argument is the allocator, and in some advanced usage of std::vector it will not be.

Commented Jun 24, 2020 At 9:39.

Since you're passing a pointer to a vector you need to. Anyway define a type instead of a macro. Everywhere qualify it by std:: Therefore the compiler needs to know the declaration of std::vector at that point (amongst other things,.</p>

You Have To Do This Because Vector Is Defined In The Std.

Vector in the function signature. Building on what ganesh said, if you arrived here anytime after 2019, you need #include and the std::vector to use a vector. You're getting the errors because u64 is not defined at that point. As some commenters have noted, you have circular references.

This However Is Rather Unwielding.

If we start in node.h, early on, it includes edge.h. Anyway define a type instead of a macro. It is not true that the type is not known. Just get iter underlying type either using decltype or using iterator.

The Type Of The Vector You Want To Create Is Of The Same Kind Of Iter.

Vector is a template, not a type, you need the template argument list e.g. The same result can however be achieved by simply including in the header file, this way you are not dependant on the order of inclusion. Template void some_func( std::vector<t,a> const& vec ) { } the second argument is the allocator, and in some advanced usage of std::vector it will not be. The code is parsed in the order it appears.